Question

porfa ayúdenme doy coronita​

Answer 1

Respuesta:

a.-

${2}^{x} = 256 \\ {2}^{x} = {2}^{8} \\ x = 8$

b.-

$\sqrt{x} = 9 \\ x = {9}^{2} \\ x = 81$

c.-

${x}^{3} = 729 \\ x = \sqrt[3]{729 } \\ x = 9$

d.-

${3}^{8} = x \\ 6561 = x$