Question

Por favorr es para ahorita :(

Answer 1

Explicación paso a paso:

$log_{4}(32) + log_{4}(2) = log_{4}(64) = (4 {}^{x} = 64) = (4 {}^{x} = 4 {}^{3} ) = 3$

$log_{27}(1) = (27 {}^{x} = 1) = (27 {}^{0} = 1) = 0$

$log_{ \sqrt{3} }( \sqrt{3} ) = ( \sqrt{3} {}^{x} = \sqrt{3} ) = 1$

$log_{ \sqrt{3} }(3) = ( \sqrt{3} {}^{x} = 3) = (( \sqrt{3} {}^{2} = 3)) = 2$

Answer 2

Respuesta:

Explicación paso a paso: