Matemáticas, pregunta formulada por jeanpierrecarrpchpw5, hace 1 año

POR FAVOR PARA AHORITA

Adjuntos:

aravaleliopariona: esta facilita
jeanpierrecarrpchpw5: AYUDAME AMIG@ COFA
aravaleliopariona: un momento
aravaleliopariona: b. (5/7)⁰ = 1

d. 5³ * 5⁴ = 5³⁺⁴ = 5⁷ = 5*5*5*5*5*5*5 = 78125

d. (-3/5)³ * (-3/5)² = (-3/5)³⁺² = (-3/5)⁵ = -3⁵/5⁵ = -243/3125

h. (2/5)⁴ * (3/5)⁴ = [(2/5)*(3/5)]⁴ = (6/25)⁴ = 6⁴/25⁴ = 1296/390625

j. (3/5)⁴ / (5/3)³ = (3⁴/5⁴) / (5³/3³) = (81/625) / (125/27) = 2187 / 78125

l. (-5)⁷/(-5)⁶ = -78125/15625 = 5

n. (5/3)² = 5²/3² = 25/9

ahi tienes amigo
aravaleliopariona: jeje
jeanpierrecarrpchpw5: gracias
jeanpierrecarrpchpw5: :3

Respuestas a la pregunta

Contestado por alexd0111aj
0

Respuesta:

Explicación paso a paso:

b. (5/7)⁰ = 1

d. 5³ * 5⁴ = 5³⁺⁴ = 5⁷ = 5*5*5*5*5*5*5 = 78125

d. (-3/5)³ * (-3/5)² = (-3/5)³⁺² = (-3/5)⁵ = -3⁵/5⁵ = -243/3125

h. (2/5)⁴ * (3/5)⁴ = [(2/5)*(3/5)]⁴ = (6/25)⁴ = 6⁴/25⁴ = 1296/390625

j. (3/5)⁴ / (5/3)³ = (3⁴/5⁴) / (5³/3³) = (81/625) / (125/27) = 2187 / 78125

l. (-5)⁷/(-5)⁶ = -78125/15625 = 5

n. (5/3)² = 5²/3² = 25/9

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