Matemáticas, pregunta formulada por kiaravalentinacarhua, hace 2 meses

por favor necesito ayuda con esto​

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Contestado por FUBUKICOOL09
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Explicación paso a paso:

1)

 {(2x - 4y)}^{2}  \\  =  {(2x)}^{2}  + 2(2x)( - 4y) +  {( - 4y)}^{2}  \\  = 4 {x}^{2}  - 16xy + 16 {y}^{2}

2)

 {(3a - 5b)}^{2}  \\  =  {(3a)}^{2}  + 2(3a)( - 5b) +  {( - 5b)}^{2}  \\  = 9 {a}^{2}  - 30ab + 25 {b}^{2}

3)

 {(6x - 5y)}^{2}  \\  =  {(6x)}^{2}  + 2(6x)( - 5y) +  {( - 5y)}^{2}  \\  = 36 {x}^{2}  - 60xy + 25 {y}^{2}

4)

 {(3x + 2y)}^{2}  \\  =  {(3x)}^{2}  + 2(3x)(2y) +  {(2y)}^{2}  \\  = 9 {x}^{2}  + 12xy + 4 {y}^{2}

5)

 {(4pq - 3q)}^{2}  \\  =  {(4pq)}^{2}  + 2(4pq)( - 3q) +  {( - 3q)}^{2}  \\  = 16 {p}^{2}  {q}^{2}   - 24pq \:  {q}^{2}  + 9 {q}^{2}

6)

 {(2 {x}^{3} - 5 {y}^{2})  }^{2}  \\  =  {(2 {x}^{3} )}^{2}  + 2(2 {x}^{3} )( - 5 {y}^{2} ) +  {( - 5 {y}^{2}) }^{2}  \\  = 4 {x}^{6}  - 20 {x}^{3} {y}^{2}  + 25 {y}^{4}

7)

 {(4 {a}^{2} - 3 {b}^{3} ) }^{2}  \\  =  {(4 {a}^{2} )}^{2}  + 2(4 {a}^{2} )( - 3 {b}^{3} ) +  {( -  {3b}^{3}) }^{2} \\  = 16 {a}^{4}   - 24 {a}^{2}  {b}^{3}  + 9 {b}^{6}

8)

 {(4 {x}^{2}  + 3 {y}^{3} )}^{2}  \\  =  {(4 {x}^{2}) }^{2}  + 2(4 {x}^{2} )(3 {y}^{3} ) +  {(3 {y}^{3}) }^{2}  \\  = 16 {x}^{4}  + 24 {x}^{2}  {y}^{3}  + 9 {y}^{6}

9)

 {(8 {a}^{2}  b + 7a {b}^{6} {y}^{2})  }^{2}  \\  =  {(8 {a}^{2} b)}^{2}  + 2(8 {a}^{2} b)(7a {b}^{6}  {y}^{2}) +  {(7a {b}^{6} {y}^{2} ) }^{2}  \\  = 64 {a}^{4}  {b}^{2}  + 112 {a}^{3}  {b}^{7}  {y}^{2}  + 49 {a}^{2}  {b}^{12}  {y}^{4}

10)

 {(13ab {x}^{2} + 2ab {y}^{3}  )}^{2}  \\  =  {(13ab {x}^{2} )}^{2}  + 2(13ab {x}^{2} )(2ab {y}^{3} ) +  {(2ab {y}^{3} )}^{2}  \\  = 169 {a}^{2}  {b}^{2}  {x}^{4}  + 52 {a}^{2}  {b}^{2}  {x}^{2}  {y}^{3}  + 4 {a}^{2}  {b}^{2}  {y}^{6}

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