Question

por favor ayúdenme urgente, con su procedimiento!​

Answer 1

Respuesta:

El lado mide 15,83 cm  :)

Explicación paso a paso:

Triangulo verde oscuro:

C $\frac{A}{H}$

Cos 28º = $\frac{8}{X}$

0,8829475929 = $\frac{8}{X}$

x = $\frac{8}{0,8829475929}$

x = 9,060560406 cm hipotenusa

Triangulo amarillo:

H = 9,060560406 cm - 2,5 cm = 6,560560406

H = 6,560560406 + 3,6 = 10,16056041 cm

C $\frac{A}{H}$

Cos 11º = $\frac{X}{10,16056041}$

0,9816271834 = $\frac{X}{10,16056041}$

x = 10,16056041 × 0,9816271834 = 9,973882298 cm adyacente

Triangulo rojo:

H = 9,973882298 cm - 2 cm = 7,973882298

H = 7,973882298 + 2,9 = 10,8738823 cm

θ = ArcSen $\frac{CO}{H}$

θ = ArcSen $\frac{3,8}{10,8738823}$

θ = 20,45436349º

T$\frac{O}{A}$

A = Tan 20,45436349º = $\frac{3,8}{X}$

A = 0,3729770986 = $\frac{3,8}{X}$

A = x = $\frac{3,8}{0,3729770986}$ = 10,1882931 cm

Triangulo celeste:

H = 10,1882931 cm - 1cm = 9,1882931

H = 9,1882931 + 3,2cm = 12,3882931 cm

C $\frac{A}{H}$

A = Cos 43º = $\frac{X}{12,3882931}$

A = 0,7313537016 = $\frac{X}{12,3882931}$

A = 12,3882931 × 0,7313537016 = 9,060224015 cm

Triangulo Morado:

A = 9,060224015 (+1-1=0)

A= 9,060224015 cm

C $\frac{A}{H}$

H = Cos 30º = $\frac{9,060224015}{X}$

H = 0,8660254038 = $\frac{9,060224015}{X}$

H = x = $\frac{9,060224015}{0,8660254038 }$ = 10,46184555 cm

Triangulo verde claro:

H = 10,46184555 cm + (3,2 + 1,9)

H = 15,56184555 cm

C $\frac{A}{H}$

A = Cos 19º = $\frac{X}{15,56184555}$

A = 0,9455185756 = $\frac{X}{15,56184555}$

A = x= 15,56184555 × 0,9455185756 = 14,71401404 cm

Triangulo naranja:

A = 14,71401404 cm - (4,8 + 1,1)

A = 8,814014038 cm

C $\frac{A}{H}$

H = Cos 46º = $\frac{8,814014038}{X}$

H = 0,6946583705 = $\frac{8,814014038}{X}$

H = x = $\frac{8,814014038}{0,6946583705}$ = 12,68827155 cm

Triangulo lila:

A = 12,68827155 cm + 1,7 cm = 14,38827155 cm

θ = ArcTan $\frac{CO}{CA}$

θ = ArcTan $\frac{3,2}{14,38827155}$

θ = 12,5386976

S $\frac{O}{H}$

H = Sen 12,5386976º = $\frac{3,2}{X}$

H = 0,2170989554 = $\frac{3,2}{X}$

H = x = $\frac{3,2}{0,2170989554}$ = 14,73982219 cm

Triangulo piel:

H = 14,73982219 cm - 2,73 cm = 12,00982219 cm

C $\frac{A}{H}$

A = Cos 22º = $\frac{X}{12,00982219}$

A = 0,9271838546 = $\frac{X}{12,00982219}$

A = x = 12,00982219 ×  0,9271838546 = 11,13531323 cm

Triangulo azul oscuro:

A = 11,13531323 cm - 2,24 = 8,89531323

A = 8,89531323 + 6,9 = 15.79531323 cm

C $\frac{A}{H}$

H = Cos 4º = $\frac{15.79531323}{X}$

H = 0,9975640503 = $\frac{15.79531323}{X}$

H = x = $\frac{15.79531323}{0,9975640503}$ = 15,83388378 cm

H ≈ 15,83 cm