Question

por favor ayudenme ​

Answer 1

Respuesta:

$h_{1} = 3\sqrt{11} \\h_{2} = - 3\sqrt{11}$

aplicando la fórmula

$g^{2} = h^{2} + ( R - r )^{2} \\10^{2} = h^{2} + ( 3 - 2 )^{2}\\100 = h^{2} + (1)^{2}\\100 =h^{2} + 1\\100 - 1 = h^{2} \\99 = h^{2} \\3\sqrt{11} =h_{1} \\-3\sqrt{11} =h_{2}$