Question

POR FAVOR AYUDA:(
>>ES PARA HOY<<​

Answer 1

Respuesta:

$(3-x)(3+x) = \\9 +3x -3x -x^{2} \\9-x^{2} \\\\\\(x-\sqrt{5} )(x+\sqrt{5} ) =\\x^{2} +x\sqrt{5}-x\sqrt{5} - \sqrt{25}\\x^{2} -\sqrt{25}\\\\\\(x^{2} -3)(-3-x^{2} ) =\\-3x^{2} -x^{4}+9+9x^{2} \\6x^{2} -x^{4} +9\\-x^{4} +6x^{2} +9\\\\\\(1-3ax)(1+3ax)=\\1+3ax-3ax-9a^{2} x^{2} \\ 1 -9a^{2} x^{2}\\\\\\(2a-1)(2a+1)\\4a^{2} +2a-2a-1\\4a^{2} -1\\\\\\(x-2)(x+3)\\x^{2} +3x-2x-6\\x^{2} +x-6\\\\\\(2a-5)(2a+6) =\\4a^{2} +12a-10a-30\\4a^{2} + 2a -30$

$(a+2)^{3} = a^{3} + 3(a)^{2}(2) + 3(a)(2)^{2} + 2^{3} \\\\a^{3} + 6a^{2} + 12a + 8\\\\\\(a-4)^{3} = a^{3} - 3(a)^{2}(-4) + 3(a)(-4)^{2}-(-4)^{3}\\\\a^{3} + 12a^{2} + 48a + 64$

Explicación paso a paso: