Question

;)por favor alguien que pueda resolver logaritmos doy coronita si no saben no respondan o los reportó ​​

Answer 1

Explicación paso a paso:

7)

log0.41(7x-21)=log0.41(2x-1)

7x-21 = 2x-1

5x = 20

x = 4

8)

log2/5[(x+3)/(3x-2)] = log2/5(2/5^(-1))

(x+3)/(3x-2) = 5/2

2(x+3) = 5(3x-2)

2x + 6 = 15x - 10

16 = 13x

x = 16/13

9)

(x+3)/4 = (2x-7)/3

3(x+3) = 4(2x - 7)

3x + 9 = 8x - 28

37 = 5x

x = 37/5

10)

27 = 3³

9 = 3²

log27(x) = log3(x)/log3(3³) = log3(x) /3

log9(x) = log3(x)/log3(3²) = log3(x)/ 2

log3(x)/3 - log3(x)/2 + log3(x) = -11/6

⅓-½+1 = 5/6

5/6log3(x) = -11/6

log3(x) = -11/5

3^(-11/5) = x

⅓^(11/5) = x