Matemáticas, pregunta formulada por Churivega, hace 1 año

Por favor 10 ejemplos de binomios al cubo es de urgencia :c

Respuestas a la pregunta

Contestado por slbrborich
1
BINOMIO AL CUBO 1)(x + 3)^3 = x^3 + 3((x)^2)(3) + 3(x)((3)^2) + (3)^3 = =x^3 + 3(x^2)(3) + 3(x)(9) + 27 = x^3 + 9x^2 + 27x + 27 ------------------------------------------------------------- 2) (2x − 3)^3 = (2x)^3 − 3((2x)^2)(3) + 3(2x)((3)^2) − (3)^3 = =8x^3 − 3(4x^2)(3) + 3(2x)(9) − 27 = 8x^3 − 36x^2 + 54 x − 27 ------------------------------------------------------- 3)(x + 2)^3 = (x)^3 + 3((x)^2)(2) + 3(x)((2)^2) + (2)^3 = =x^3 + 3(x^2)(2) + 3(x)(4) + 8 = x^3 + 6x^2 + 12x + 8 ----------------------------------------------------------------- 4)(3x − 2)^3 = (3x)^3 − 3((3x)2)(2) + 3(3x)((2)^2) − (2)^3 = 27x^3 − 3(9x^2)(2) + 3(3x)(4) − 8 = 27x^3 − 54x^2 + 36x − 8 ---------------------------------------------------------------------------- 5)(2x + 5)^3 = (2x)^3 + 3((2x)^2)(5) + 3(2x)((5)^2) + (5)^3 = =8x^3 + 3(4x^2)(5) + 3(2x)(25) + 125 = 8x^3 + 60x^2 + 150 x + 125 ------------------------------------------------------------------------------- 6)(2X+1)^3=(2x)^3 + 3((2x)^2)(1) + 3(2x)((1)^2) + (1)^3 = =8x^3 + 3(4x^2)(1) + 3(2x)(1) + 125 =8X^3+12x^2+6x+1 ------------------------------------------------------------------------------- 7)(2x^2-3y^3)^3=((2x^2)^3 - 3((2x^2)^2)(3y^3) + 3(2x^2)((3y^3)^2) - (3y^3)^3 = =8x^6 - 3(4x^4)(3y^3) + 3(2x^2)(9y^6) -27y^9 =8x^6-36x^4y^3+5x^2y^6-27y^9 ------------------------------------------------------------------------------------- 8)(1+4a)^3=(1)^3 + 3((1)^2)(4a) + 3(1)((4a)^2) + (4a)^3 = =1^3 + 3(1)(4a) + 3(1)(16a^2) + 64a^3 =1+12a+48a^2+64a^3 -------------------------------------------------------------------------------------- 9)(a^3-6b^5)^3=((a^3)^3 - 3((a^3)^2)(6b^5) + 3(a^3)((6b^5)^2) - (6b^5)^3 = a^9 - 3(a^6)(6b^5) + 3(a^3)(36b^10) - 216b^15 a^9-18a^6b^5+108a^3b^10-216b^15 ------------------------------------------------------------------------------------------ 10)(a^3+1)^3=(a^3)^3 + 3((a^3)^2)(1) + 3(a^3)((1)^2) + (1)^3 = a^9 + 3(a^6)(1) + 3(a^3)((1)^2) + (1)^3 a9+3a^6+3a+1 ------------------------------------------------------------------------------------------ BINOMIO CONJUGADO 1)(m + f)(m - f) = (m)^2 - (f)^2 =m^2 - f^2 ------------------------------------------------------------------------------- 2)(2x^2 + y)(2x^2 - y) = (2x^2)^2 - (y)^2 =4x^4 - y^2 -------------------------------------------------------------------------------------- 3)(a + bc) (a – bc) = (a)^2 - (bc)^2 =a^2 - b^2c^2 ------------------------------------------------------------------------------------- 4)(5m^3 – 7n^2) (5m^3 + 7n^2) =(5m^3)^2 - (7n^2)^2 =25m^6 - 49n^4 -------------------------------------------------------------------------------------- 5) (a/b + 8) (a/b – 8) = (a/b)^2 - (8)^2 a^2/b^2 - 64 ---------------------------------------------------------------------------------------- 6)(m + 1)(m - 1) = (m)^2 - (1)^2 =m^2 - 1 ------------------------------------------------------------------------------- 7)(4c^2 + z)(4c^2 - z) = (4c^2)^2 - (z)^2 =16c^4 - z^2 -------------------------------------------------------------------------------------- 8)(ab + cd) (ab – cd) = (ab)^2 - (cd)^2 =a^2b^2 - c^2d^2 ------------------------------------------------------------------------------------- 9)(3e^3 – 2j^2) (3e^3 + 2j^2) =(3e^3)^2 - (2j^2)^2 =9e^6 - 4j^4 -------------------------------------------------------------------------------------- 10) (b/a + x) (a/b – 8) = (b/a)^2 - (8)^2 b^2/a^2 - x^2 ----------------------------------------------------------------------------------------
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