Question

por fa aiuda es primer año :(​

Answer 1

Respuesta:

$a) {( \frac{3}{5} )}^{2} = \frac{9}{25}$

$b) {( - \frac{3}{5} )}^{2} = \frac{9}{25}$

$c) - {( \frac{3}{5} )}^{2} = - \frac{9}{25}$

$d) - {( - \frac{3}{5} )}^{2} = - \frac{9}{25}$

$e) {( - \frac{8}{17} )}^{0} = 1$

$f) {( \frac{17}{6} )}^{1} = \frac{17}{6}$

$g) - {( \frac{17}{6} )}^{0} = - 1$

$h) {( - \frac{13}{7} )}^{0} = 1$

$i) - {( - \frac{13}{7} )}^{0} = - 1$

$j) {( - \frac{3}{10} )}^{3} = - \frac{27}{1000}$

$k) \sqrt{ \frac{49}{25} } = \frac{7}{5}$

$l) \sqrt[3]{ \frac{1}{1000} } = \frac{1}{10}$

$m) \sqrt[3]{ - \frac{8}{27} } = - \frac{2}{3}$

$n) \sqrt[4]{ \frac{81}{16} } = \frac{3}{2}$

$ñ) \sqrt[5]{ - \frac{1}{32} } = - \frac{1}{2}$

$o) {( \frac{3}{4} )}^{ - 3} = {( \frac{4}{3} )}^{3} = \frac{64}{27}$

$p) {( - \frac{8}{7} )}^{ - 1} = {( - \frac{7}{8} )}^{1} = - \frac{7}{8}$

$q) {( - \frac{5}{7} )}^{ - 2} = {( - \frac{7}{5} )}^{2} = \frac{49}{25}$

$r) {( - 2)}^{ - 5} = {( - \frac{1}{2} )}^{5} = - \frac{1}{32}$

$s) - {( - \frac{3}{10} )}^{ - 1} = - {( - \frac{10}{3} )}^{1} = - ( - \frac{10}{3} ) = \frac{10}{3}$