Question

pofavor alludenmen con estas taresas no me ignoren​

Answer 1

RESOLVER:

Nota: Las respuestas las ordené de forma de abecedario, eso es para que se me haga más fácil ya ti también.

a) $\left(2x+3\right)\left(3-r\right)-\left(2x-5\right)\left(3-r\right)$

En estos paréntesis juntos, lo que vamos hacer sería expandir los términos

$\left(2x+3\right)\left(3-r\right)=6x-2xr+9-3r$

$=6x-2xr+9-3r-\left(2x-5\right)\left(3-r\right)$

$\left(2x-5\right)\left(3-r\right)=-6x+2xr+15-5r$

$=6x-2xr+9-3r-6x+2xr+15-5r$

$\boxed{=-8r+24}$

b) $a\left(x+1\right)+b\left(x+1\right)$

$a\left(x+1\right):ax+a$

$=ax+a+b\left(x+1\right)$

$b\left(x+1\right):bx+b$

$\boxed{=ax+a+bx+b}$

c) $x\left(a+1\right)-3\left(a+1\right)$

$x\left(a+1\right):ax+x$

$=ax+x-3\left(a+1\right)$

$3\left(a+1\right):-3a-3$

$\boxed{=ax+x-3a-3}$

d) $2\left(x-1\right)+y\left(x-1\right)$

$2\left(x-1\right):2x-2$

$=2x-2+y\left(x-1\right)$

$y\left(x-1\right):xy-y$

$\boxed{=2x-2+xy-y}$

e) $m\left(a-b\right)+\left(a-b\right)$

$m\left(a-b\right)+\left(a-b\right)=m\left(a-b\right)+a-b$

$=m\left(a-b\right)+a-b$

$m\left(a-b\right):ma-mb$

$\boxed{=ma-mb+a-b}$

f) $2x\left(n-1\right)+3y\left(n-1\right)$

$2x\left(n-1\right):2nx-2x$

$=2nx-2x+3y\left(n-1\right)$

$3y\left(n-1\right):3ny-3y$

$\boxed{=2nx-2x+3ny-3y}$

g) $a\left(n+2\right)+n+2$

$a\left(n+2\right)=an+a\cdot \:2$

$=an+a\cdot \:2+n+2$

$\boxed{=na+2a+n+2}$

h) $x\left(a+1\right)-a-1$

$x\left(a+1\right)=xa+x\cdot \:1$

$=xa+x\cdot \:1-a-1$

$xa+x\cdot \:1:ax+x$

$\boxed{=ax+x-a-1}$

i) $a^2+1-b\left(a^2+1\right)$

$-b\left(a^2+1\right)=-ba^2-b\cdot \:1$

$=a^2+1-ba^2-b\cdot \:1$

$-ba^2-b\cdot \:1:-a^2b-b$

$\boxed{=a^2+1-a^2b-b}$

j) $3x\left(x-2\right)-2y\left(x-2\right)$

$3x\left(x-2\right):3x^2-6x$

$=3x^2-6x-2y\left(x-2\right)$

$-2y\left(x-2\right):-2xy+4y$

$\boxed{=3x^2-6x-2xy+4y}$

k) $1-x+2a\left(1-x\right)$

$2a\left(1-x\right)=2a\cdot \:1-2ax$

$=1-x+2a\cdot \:1-2ax$

$\boxed{=1-x+2a-2ax}$

l) $a^3\left(a-b+1\right)-b^2\left(a-b+1\right)$

$a^3\left(a-b+1\right):a^4-a^3b+a^3$

$=a^4-a^3b+a^3-b^2\left(a-b+1\right)$

$b^2\left(a-b+1\right):-ab^2+b^3-b^2$

$\boxed{=a^4-a^3b+a^3-ab^2+b^3-b^2}$

m) $4m\left(a^2+x-1\right)+3n\left(x-1+a^2\right)$

$4m\left(a^2+x-1\right):4ma^2+4mx-4m$

$3n\left(x-1+a^2\right):3nx-3n+3a^2n$

$\boxed{=4ma^2+4mx-4m+3nx-3n+3a^2n}$

n) $x\left(2a+b+c\right)-2a-b-c$

$x\left(2a+b+c\right)=x\cdot \:2a+xb+xc$

$=x\cdot \:2a+xb+xc-2a-b-c$

$\boxed{=2ax+bx+cx-2a-b-c}$

o) $\left(x+y\right)\left(n+1\right)-3\left(n+1\right)$

$\left(x+y\right)\left(n+1\right):nx+x+ny+y$

$=nx+x+ny+y-3\left(n+1\right)$

$-3\left(n+1\right):-3n-3$

$\boxed{=nx+x+ny+y-3n-3}$

p) $\left(x+1\right)\left(x-2\right)+3y\left(x-2\right)$

$\left(x+1\right)\left(x-2\right):x^2-x-2$

$=x^2-x-2+3y\left(x-2\right)$

$3y\left(x-2\right):3xy-6y$

$\boxed{=x^2-x-2+3xy-6y}$

Como te dije, primero solucionamos el interior del paréntesis, luego que ya lo hayamos hecho, solo nos quedaría simplificar.

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