Question

podrian resolverlo porfavor aaaa<\3

Answer 1

Respuesta:

$(3 + \sqrt{( {4}^{3} \div 4 - 13) + 1 } ) \div 5 \\ (3 + \sqrt{(16 - 13) + 1} ) \div 5 \\ (3 + \sqrt{3 + 1} ) \div 5 \\ (3 + \sqrt{4} ) \div 5 \\ (3 + 2) \div 5 \\ 5 \div 5 = 1$

${3}^{2} \div \sqrt{9} - {2}^{3} \div \sqrt{4} + {4}^{2} \div \sqrt[3]{8} \\ 9 \div 3 - 8 \div 2 + 16 \div 2 \\ 3 - 4 + 8 \\ - 1 + 8 = 7$