Question

Po favor, señalar procedimiento y encontrar el valor de CH​

Answer 1

Desarrollo:

$Ecuaciones\\12^{2} = PH^{2} +RH^{2} \\ RQ^{2} = 7^{2} +RH^{2} \\ (PH+7)^{2} = 12^{2} +RQ^{2} \\\\ 12^{2} = PH^{2} +RH^{2} \\ RH^{2} = 144 - PH^{2} \\\\ (PH+7)^{2} = 12^{2} +RQ^{2} \\ PH^{2} + 14PH + 49 = 144 + RQ^{2} \\ RQ^{2} = PH^{2} + 14PH - 95 \\\\ RQ^{2} = 7^{2} +RH^{2} \\ PH^{2} + 14PH - 95 = 49 + 144 - PH^{2} \\ 2PH^{2} + 14PH - 288 = 0 \\ PH^{2} + 7PH - 144 = 0 \\ (PH +16)(PH-9) = 0 \\\\ PH + 16 = 0 \\ PH = -16 \\\\ PH -9 = 0 \\ PH = 9$

Respuesta: Opción A