Question

please please please​

Answer 1

Respuesta:

F = 0

Explicación paso a paso:

$F=\sqrt[5]{\left(x+y\right)^2-\left(x-y\right)^2-4xy}$

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• $\left(x+y\right)^2-\left(x-y\right)^2-4xy$

$=x^2+2xy+y^2-\left(x-y\right)^2-4xy\\=x^2+2xy+y^2-\left(x^2-2xy+y^2\right)-4xy\\=x^2+2xy+y^2-x^2+2xy-y^2-4xy\\=x^2-x^2+2xy+2xy-4xy+y^2-y^2\\=2xy+2xy-4xy+y^2-y^2\\=y^2-y^2\\=0$

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$F=\sqrt[5]{0}\\F=0$