peso molecular de los siguientes compuestos
1.-acido selenioso
2.-sulfato de cadnio
3.-acido fosforico
4.-bromato de potacio
5.-silicato de plata
Respuestas a la pregunta
Contestado por
1
1.H2SeO3
H: 2 x 1 = 2 g/mol
Se:1 x 79 = 79 g/mol
O:3 x 16 = 48 g/mol
``````````````````````````
Mm = 129 g/mol
2. CdSO4
Cd: 1 x 112 = 112 g/mol
S: 1 x 32 = 32 g/mol
O: 4 x 16 = 64 g/mol
````````````````````````````````
Mm = 208 g/mol
3. H3PO4
H: 3 x 1 = 3 g/mol
P= 1 x 3 = 31 g/mol
O:4 x 16 =64 g/mol
``````````````````````````````
Mm = 98 g/mol
4. KBrO3
K: 1 x 39 = 39 g/mol
Br: 1 x 80 = 80 g/mol
O: 3 x 16 = 48 g/mol
``````````````````````````````
Mm = 167 g/mol
5. Ag2SiO3
Ag: 2 x 107,86 = 215.72 g/mol
Si: 1 x 28 = 28 g/mol
O: 3 x 16 = 48 g/mol
````````````````````````````````
Mm = 291.72 g/mol
H: 2 x 1 = 2 g/mol
Se:1 x 79 = 79 g/mol
O:3 x 16 = 48 g/mol
``````````````````````````
Mm = 129 g/mol
2. CdSO4
Cd: 1 x 112 = 112 g/mol
S: 1 x 32 = 32 g/mol
O: 4 x 16 = 64 g/mol
````````````````````````````````
Mm = 208 g/mol
3. H3PO4
H: 3 x 1 = 3 g/mol
P= 1 x 3 = 31 g/mol
O:4 x 16 =64 g/mol
``````````````````````````````
Mm = 98 g/mol
4. KBrO3
K: 1 x 39 = 39 g/mol
Br: 1 x 80 = 80 g/mol
O: 3 x 16 = 48 g/mol
``````````````````````````````
Mm = 167 g/mol
5. Ag2SiO3
Ag: 2 x 107,86 = 215.72 g/mol
Si: 1 x 28 = 28 g/mol
O: 3 x 16 = 48 g/mol
````````````````````````````````
Mm = 291.72 g/mol
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