Question

Para ayer porfavor...

Answer 1

$\frac{2x-3a}{x+4a}-2 = \frac{11a}{x^{2}-16a^{2}} \\\\\frac{2x-3a -2(x+4a)}{x + 4a} = \frac{11a}{(x+4a)(x - 4a)}\\\\\frac{2x-3a -2x-8a}{x + 4a} = \frac{11a}{(x+4a)(x - 4a)}\\\\ 2x-3a -2x-8a = \frac{11a}{x - 4a}\\\\-3a - 8a = \frac{11a}{x - 4a}\\\\-11a = \frac{11a}{x - 4a}\\\\-11a(x-4a) = 11a\\\\x -4a = -\frac{11a}{11a}\\\\x - 4a = -1\\\\x = 4a - 1$

Eternamente axllxa