Question

p = {x€N/x²-9=0}
Q = {X€Z/x²-9=0}
F = {x€R/x²+9=0}
T = {x€Q/(3x-4)(x-√2)=0}
B = {x € I/(3x-4)(x-√2)=0}​

Answer 1

Respuesta:

Explicación paso a paso:

P = {x€N/x²-9=0}

x² - 9 = 0

x² = 9

x = ±$\sqrt{9}$ = ± 3

P = { 3 }

Q = {X€Z/x²-9=0}

Q = { -3 , 3 }

F = {x€R/x²+9=0}

x² = -9  no existe solución en |R

F = ϕ   conjunto vacio

T = {x€Q/(3x-4)(x-√2)=0}

(3x-4)(x-√2)=0 ⇔ 3x - 4 = 0  ∧ x - $\sqrt{2}$ = 0

                                x = 4/3   ∧ x = $\sqrt{2}$

T = { 4/3 }

B = {x € I/(3x-4)(x-√2)=0}​

B = {$\sqrt{2}$}