Question

p(x)=6x²+5y²-3x+y-15 ayudaaaaa​

Answer 1

1) p(x)=6x²+5y²-3x+y-15=

p'(x)=d/DX (6x²+5y²-3x+y-15)

p' (x=d/dx(6x²)+d/dx(5y²)+d/dx(-3x)+d/dx(y) -d/dx (15)

p'(x)= 6×2x+10-3+0-0

p'(x)= 12x-3

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2) q(x)= -x²+2y²+12+6xy=

q'(x)= d/dx (-x²+2y²+12+6xy)

q'(x)= d/dx (-x²+2y²+12+6yx)

q'(x) -d/DX (x²) +d/dx(2y²)+ d/dx(12)+d/dx(6yx)

q'(x)=-2x+0+0+6y

q'(x)= -2x+6y

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3) Q(x)-x²+2y²+12+6+y=

Q(x)-x²+2y²+12+6+y

Qx-x²+2y²+12+6+y

Qx-x²+2y²+18+y

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4) R(x)=-5x⁴+7x³+y²+2xy-9=

R'(x)=d/dx (-5x⁴+7x³+y²+2xy-9)

R'(x)=d/dx (-5x⁴+7x³+y²+2yx-9)

R'(x)=d/dx (-5x⁴)+d/dx(7x³)+d/dx(y²)+d/dx(2yx)-d/dx(9)

R'(x)=-5×4x³+7×3x²+0+2y-0

R'(x)=-20x³+21x²+2y

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5) S(x)=-3xy+x³-2y²+8=

S'(x)=d/dx(-3xy+x³-2y²+8)

S'(x)=d/dx(-3yx+x³-24²+8)

S'(x)=d/dx(-3yx)+d/dx(x³)+d/dx(-2y²)+d/dx(8)

S'(x)=-3y+3x²+0+0

S'(x)=-3y+3x²

Espero y te sirva.

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A) P(x)+q(x)=

p(x)+q(x)=px+xq

p(x)+q(x)

px+qx

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