Question

operaciones:


a)√3×(√2+√3)=

b) (√216+√376) ÷2=

c) (√20-√108)×2√5=




​

Answer 1

Explicación paso a paso:

a)√3×(√2+√3)

= √3×√2 + √3×√3

= √(3×2) + √(3×3)

= √6 + √9

= 2,45 + 3

= 5,45

b) (√216+√376) ÷2

= [√(36×6) + √(47×2×4)] /2

= [6√6 + 2√94]/2

= 2[3√6 + √94]/2

= 3√6 + √94

= 7,35 + 9,7

= 17,05

c) (√20 - √108) × 2√5

= [√(4×5) + √(36×3)] × 2√5

= [2√5 + 6√3] × 2√5

= (2√5 × 2√5)+ (6√3 × 2√5)

= 20 + 12√15

= 20 + 12(3,87)

= 66,44