Question

obtener el diferencial ​

Answer 1

Respuesta:

Explicación:

f'(x)=d/dx[(x²+5)²]⋅(x−2)²−(x²+5)²⋅d/dx[(x−2)²] / [(x−2)²]²

f´(x)=2(x²+5)⋅d/dx[x²+5]⋅(x−2)²−(x²+5)²⋅2(x−2)⋅d/dx[x−2] / (x−2)⁴

f'(x)=2(x²+5)(d/dx[x²]+d/dx[5])(x−2)²−(x²+5)²⋅2(x−2)(d/dx[x]+d/dx[−2]) / (x−2)⁴

f'(x)==2(x²+5)(2x+0)(x−2)²−(x²+5)²⋅2(x−2)(1+0)/(x−2)⁴

f'(x)=4(x−2)²x⋅(x²+5)−2(x−2)(x²+5)² /(x−2)⁴

Reescribir y simplificar

f'(x)=4x⋅(x²+5)(x−2)²−2(x²+5)²/(x−2)³

f'(x)=2(x²+5)(x²−4x−5) / (x−2)³