Question

Numeros raccionales, porfavor es para en una hora

Answer 1

Respuesta:

1)

a)$\frac{32}{5} = 6.4$

b)$\frac{52}{25} = 2.08$

c)$\frac{28}{6} = 4.6...$

d)$\frac{311}{90} = 3.455...$

e)no leo bien

2)

a) $\frac{8}{13} = \frac{16}{26} = \frac{40}{65} = \frac{32}{52}$

b)$\frac{12}{5} = \frac{24}{10} = \frac{36}{15} = \frac{60}{25}$

c)$\frac{18}{20} = \frac{9}{10} = \frac{45}{50} = \frac{36}{40}$

d)$-\frac{9}{4} = -\frac{18}{8} = -\frac{36}{16} = -\frac{45}{20}$

3)

a) $\frac{5}{12}$ , $\frac{2}{5}$

b) $\frac{37}{20}$ , $\frac{9}{5}$

c) $\frac{12}{9}$ , $\frac{13}{10}$

d) $\frac{7}{8}$ , $\frac{9}{10}$

4)

a) $- \frac{5}{4}$

b) $\frac{107}{60}$

c) $\frac{9}{10}$

Explicación paso a paso:

Bueno, lo intenté lo mejor que pude, pero no estoy seguro si existen errores, lo siento.

4)

a)

$1...-\frac{7}{8} +\frac{1}{4} *(\frac{2}{3} -\frac{3}{2} )-\frac{2}{4}/3\\2...-\frac{7}{8} +\frac{1}{4}*(-\frac{5}{6})-\frac{1}{2} /3\\3... -\frac{7}{8}-\frac{5}{24} -\frac{1}{6}\\4...-\frac{5}{4}$

b)

$1...(-\frac{2}{3} )^{5}/ (-\frac{2}{3} )^{7} +\frac{3}{10} /4^{-1} -\sqrt{(\frac{1}{2}+\frac{1}{3} )\frac{10}{3} } \\2...(-\frac{2}{3})^{-2} +\frac{6}{5} -\sqrt{\frac{5}{6}*\frac{10}{3} } \\3...(-\frac{3}{2})^{2} +\frac{6}{5} -\sqrt{\frac{5}{3}*\frac{5}{3} }\\4...(\frac{9}{4})+\frac{6}{5}-\frac{5}{3} \\5...\frac{107}{60}$

c)

$1...\sqrt{(6-\frac{7}{3})*\frac{11}{12} } + (1-\frac{5}{3} )^{2} * \frac{12}{5} -2\\2...\sqrt{\frac{11}{3}*\frac{11}{12} } + (-\frac{2}{3} )^{2} * \frac{12}{5} -2\\3...\sqrt{\frac{121}{36} } + (-\frac{2}{3} )^{2} * \frac{12}{5} -2\\4...\sqrt{\frac{121}{36} } + \frac{4}{9} * \frac{12}{5} -2\\5...\frac{11}{6} +\frac{4}{9}*\frac{12}{5}-2\\6...\frac{11}{6}+\frac{16}{15}-2\\7...\frac{9}{10}$