Matemáticas, pregunta formulada por kellybelduma4, hace 16 horas

Nesecito ayuda en esta tarea​

Adjuntos:

kellybelduma4: les doy coronita pero ayúdenme
kellybelduma4: es para hoy

Respuestas a la pregunta

Contestado por JMSuarez2007
1

Respuesta:

 \sqrt{ \frac{121}{100} }  \times  \frac{10}{8}  +  \frac{3}{5}  \div  \frac{4}{10}  =  \frac{ \sqrt{121} }{ \sqrt{100}}  \times  \frac{10}{8}  +  \frac{3}{5}  \times  \frac{10}{4}  =  \frac{11}{10}   \times  \frac{10}{8}  +  \frac{3 \times 10}{5 \times 4}  =  \frac{11 \times 10}{10 \times 8}  +  \frac{30}{20}  =  \frac{110}{80}  +  \frac{30}{20}  =  \frac{110 + 120}{80}  =  \frac{230}{80}  =  \frac{23}{8}

( \frac{2}{5}  + 1) + ( \frac{3}{5}  \div  \frac{4}{10} ) = ( \frac{2}{5}  +  \frac{1}{1} ) + ( \frac{3}{5}  \times  \frac{10}{4} ) =  ( \frac{2 + 5}{5} ) + ( \frac{3 \times 10}{5 + 4} ) = ( \frac{7}{5} ) + ( \frac{30}{20} ) =  \frac{7}{5}  +  \frac{30}{20}  =  \frac{28 + 30}{20}  =  \frac{58}{20}  =  \frac{29}{10}

 \sqrt[3]{ \frac{512}{27} }  \times  \frac{7}{8}  -  \frac{2}{5}  \div  \frac{6}{10}  =  \frac{ \sqrt[3]{512} }{ \sqrt[3]{27} }  \times  \frac{7}{8}  -  \frac{2}{5}  \times  \frac{10}{6}  =  \frac{8}{3}  \times   \frac{7}{8}  -  \frac{2 \times 10}{5 \times 6}  =  \frac{8 \times 7}{3 \times 8}  -  \frac{20}{30}  =  \frac{56}{24}  -  \frac{20}{30}  =  \frac{280 - 80}{120}  =  \frac{200}{120}  =  \frac{5}{3}

( \frac{1}{2}  +  \frac{2}{5} ) {}^{2}  +  \frac{3}{5}  \times  \frac{3}{2}  +  \frac{4}{5}  \div  \sqrt{ \frac{16}{4} }  = ( \frac{5 + 4}{10} ) {}^{2}  +  \frac{3 \times 3}{5 \times 2}  +  \frac{4}{5}  \div  \frac{ \sqrt{16} }{ \sqrt{4} }  = ( \frac{9}{10} ) {}^{2}  +  \frac{9}{10}  +  \frac{4}{5}  \div  \frac{4}{2}  =  \frac{ {9}^{2} }{ {10}^{2} }  +  \frac{9}{10}  +  \frac{4}{5}  \times  \frac{2}{4}  =  \frac{81}{100}  +  \frac{9}{10}  +  \frac{4 \times 2}{5 \times 4}  =  \frac{81 + 90}{100}  +  \frac{8}{20}  =  \frac{171}{100}  +  \frac{8}{20}  =  \frac{171 + 40}{100}  =  \frac{211}{100}

Otras preguntas