Question

Necesito saber las soluciones a todos los apartados excepto el a) que ya está hecho, por favor ayudadme también os sirve de entrenamiento de mates

Answer 1

APARTADO (b)
- 8 = (x - 1)/4
4 (- 8) = x - 1
- 32 = x - 1
- 32 + 1 = x
- 31 = x
x = - 31

Rpt. El valor de x es - 31
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APARTADO (c)
(2x + 3)/3 = x - 5
2x + 3 = 3 (x - 5)
2x + 3 = 3x - 15
2x - 3x = - 15 - 3
- x = - 18
x = 18

Rpt. El valor de x es 18
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APARTADO (d)
3/4 = 1 - x/2
3/4 = (2 * 1 - x)/2
3/4 = (2 - x)/2
2 (3) = 4 (2 - x)
6 = 8 - 4x
4x = 8 - 6
4x = 2
x = 2/4
x = 1/2

Rpt. El valor de x es 1/2
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APARTADO (e)
12x/3 = 3x/2 + 2
12x/3 = (2 * 2 + 3x)/2
12x/3 = (4 + 3x)/2
2 (12x) = 3 (4 + 3x)
24x = 12 + 9x
24x - 9x = 12
15x = 12
x = 12/15
x = 4/5

Rpt. El valor de x es 4/5
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APARTADO (f)
(x + 1)/6 - (x - 4)/3 = 9/4
6 (x + 1)/6 - 6 (x - 4)/3 = 6 (9/4)
(x + 1) - 2 (x - 4) = 54/4
x + 1 - 2x + 8 = 54/4
x - 2x + 1 + 8 = 54/4
- x + 9 = 54/4
- x = 54/4 - 9
- x = (- 9 * 4 + 54)/4
- x = (- 36 + 54)/4
- x = 18/4
- x = 9/2
x = - 9/2

Rpt. El valor de x es - 9/2

LISTO°

Answer 2

a) (x+3) / 3 = x+5
x+3 = (3)(x+5)
x+3 = 3x+15
x-3x= 15-3
-2x = 12
x = -6

b) -8 = (x-1) /4
-8(4) = x-1
-32 = x-1
-32+1 = x
-31 = x

c) (2x+3) /3 = x-5
2x+3 = (3)(x-5)
2x+3 = 3x-15
3+15 = 3x-2x
18 = x

d) 3/4 = 1 - (x/2)
3/4 = (2-x) /2
3(2) = (4)(2-x)
6 = 8-4x
4x = 8-6
4x=2
x=2/4
x= 1/2

e) 12x /3 = 3x /2 + 2
12x /3 = (3x+4) /2
(12x)(2) = (3)(3x+4)
24x = 9x+12
24x - 9x = 12
15x = 12
x= 12/15 --- sacas tercia
x= 4/5

f) (x+1) /6 - (x-4) /3 = 9/4
(x+1 - 2x+8) /6 = 9/4
4 (x+1-2x+8) = (6)(9)
4x+4-8x+32 = 54
36-4x=54
36-54 = 4x
-18 = 4x
-18 /4 =x --- sacas mitad
-9/2 = x