Question

Necesito resultado con procedimientos
3(x+1/3)=1/x-1/3

Answer 1

Respuesta:

$x_{1} =}$ (-2 + √(2² - 4(9)(-3))/18= (-2 + √(112))/18

$x_{2} =$ (-2 - √(2² - 4(9)(-3))/18= (-2 - √(112))/18

Explicación paso a paso:

$3*(x+\frac{1}{3} )=\frac{1}{x} -\frac{1}{3}$

3x + 1 = $\frac{1}{x} + \frac{1}{3}$

3x - $\frac{1}{x} = \frac{1}{3} -1$

$\frac{3x^{2}-1 }{x} =-\frac{2}{3}$

3(3x²-1) = -2x

9x² +2x - 3 = 0

Por fórmula general:

$x_{1,2} =$ (-b ±√(b² - 4ac))/2a

$x_{1} =}$ (-2 + √(2² - 4(9)(-3))/18= (-2 + √(112))/18

$x_{2} =$ (-2 - √(2² - 4(9)(-3))/18= (-2 - √(112))/18