Matemáticas, pregunta formulada por xtina, hace 1 año

NECESITO RESOLVER EL SIGUIENTE EJERCICIO:

(2/3 - 1/6)2 – ( 3/2 )-2  – (- ¼)-1 :8/3 –(- 1)-2

Respuestas a la pregunta

Contestado por cristinalaguapa123
11
((2)/3-(1)/6)*2-(3)/2-2-(-1)/4-((1)/8)/3--1-2

(2/3-1/6)*2-3/2-2--1/4-1/(8*3)+1-2
common denominator is 6

((2*2)/(2*3)-(1)/6)*2-3/2-2--1/4-1/(8*3)+1-2

((4)/6-(1)/6)*2-3/2-2--1/4-1/(8*3)+1-2

1/2*2-3/2-2--1/4-1/(8*3)+1-2

1-3/2-2--1/4-1/(8*3)+1-2
eliminate minuses

1-3/2-2+1/4-1/(8*3)+1-2

1-3/2-2+1/4-1/24+1-2

-79/24


Contestado por cristhianvl2002
1

Respuesta: -79/24

(2)/3-(1)/6)*2-(3)/2-2-(-1)/4-((1)/8)/3--1-2

(2/3-1/6)*2-3/2-2--1/4-1/(8*3)+1-2

common denominator is 6

((2*2)/(2*3)-(1)/6)*2-3/2-2--1/4-1/(8*3)+1-2

((4)/6-(1)/6)*2-3/2-2--1/4-1/(8*3)+1-2

1/2*2-3/2-2--1/4-1/(8*3)+1-2

1-3/2-2--1/4-1/(8*3)+1-2

eliminate minuses

1-3/2-2+1/4-1/(8*3)+1-2

1-3/2-2+1/4-1/24+1-2

-79/24

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