Necesito resolver
(0,2 x - 1) +1,2= 0,5 + x
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0,2= 2/10 ; 1,2= 12/10 ; 0,5=5/10.
[tex]\frac{2}{10} x - 1 + \frac{12}{10} = \frac{5}{10} + x \\ \frac{2x - 10}{10} + \frac{12}{10} = \frac{10x+5}{10} \\ \frac{2x + 2}{10} = \frac{10x+5}{10} \\ 2x + 2 = 10x+5 \\ x = \frac{-3}{8}
[tex]\frac{2}{10} x - 1 + \frac{12}{10} = \frac{5}{10} + x \\ \frac{2x - 10}{10} + \frac{12}{10} = \frac{10x+5}{10} \\ \frac{2x + 2}{10} = \frac{10x+5}{10} \\ 2x + 2 = 10x+5 \\ x = \frac{-3}{8}
baptist:
=0,5 + x
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