Question

Necesito que me ayuden con este ejercicio de química

Answer 1

Respuesta:

Espero haberle ayudado :) XDXDXDXDXDXDXD

Explicación:

A.

Fe: 2 × 56 = 112 ÷ 352 = 0.318 × 100 = 31.8%

S: 1 × 3 × 32 = 96 ÷ 352 = 0.272 × 100 = 27.2%

O: 3 × 3 × 16 = 144 ÷ 352 = 0.409 × 100 = 40.9%

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352g/mol

B.

K: 2 × 39 = 78 ÷ 293.8 = 0.265 × 100 = 26.5% Cr: 2 × 51.9 = 103.8 ÷ 293.8 = 0.353 × 100 =35.3%

O: 7 × 16 = 112 ÷ 293.8 = 0.381 × 100 = 38.1%

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293.8g/mol

C.

Zn: 1 × 65 = 65 ÷ 264 = 0.246 × 100 = 24.6%

Cl: 1 × 2 × 35.5 = 71 ÷ 264 = 0.268 × 100 =26.8%

O: 4 × 2 × 16 = 128 ÷ 264 = 0.484 × 100 = 48.4%

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264g/mol

D.

H: 3 × 1 = 3 ÷ 141.9 = 0.021 × 100 = 2.1

As: 1 × 74.9 = 74.9 ÷ 141.9 = 0.527 × 100 = 52.7%

O: 4 × 16 = 64 ÷ 141.9 = 0.451 × 100 = 45.1%

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141.9g/mol