Question

necesito que me ayuden​

Answer 1

Hola!

Explicación paso a paso:

$a) \: (6 {x}^{5} ) \div (2 {x}^{3} ) = \frac{6 {x}^{5} }{2 {x}^{3} } = 3 {x}^{5 - 3} = 3 {x}^{2} \\ \\ b) \: ( - 9{x}^{3} ) \div (3{x}^{2} ) = \frac{ - 9 {x}^{3} }{3{x}^{2} } = - 3 {x}^{3 - 2} = - 3x \\ \\ c) \: ( 4{x}^{5} ) \div ( - 2{x}^{5} ) = \frac{ 4{x}^{5} }{ - 2 {x}^{5} } = - 2{x}^{5 -5 } = - 2{x}^{0} = - 2\\ \\ d) \: ( 4{x}^{5} ) \div (5 {x}^{4} ) = \frac{ 4{x}^{5} }{ 5{x}^{4} } = \frac{5}{4} {x}^{ 5- 4} = \frac{5}{4} x = \frac{5x}{4} \\ \\ e) \: (7 {x}^{7} ) \div (3 {x}^{4} ) = \frac{ 7{x}^{7} }{ 3{x}^{4} } = \frac{7}{3} {x}^{7 - 4} = \frac{7}{3} {x}^{3} = \frac{7{x}^{3} }{3} \\ \\ f) \: (5 {x}^{6} ) \div ( - 2 {x}^{3} ) = \frac{ 5{x}^{6} }{ - 2 {x}^{3} } = - \frac{5}{2} {x}^{ 6-3 } = - \frac{5}{2} {x}^{3} = - \frac{5 {x}^{3} }{2} \\ \\ g) \: ( - 2{x}^{6} ) \div (5 {x}^{2} ) = \frac{ - 2{x}^{6} }{ 5{x}^{2} } = - \frac{2}{5} {x}^{6 -2 } = - \frac{2}{5} {x}^{4} = - \frac{2 {x}^{4} }{5} \\ \\ h) \: ( - 3 {x}^{4} ) \div ( - 2x) = \frac{ - 3 {x}^{4} }{ - 2x} = \frac{3}{2} {x}^{4 - 1} = \frac{3}{2} {x}^{3} = \frac{3 {x}^{3} }{2} \\ \\ y) \: (7 {x}^{4} ) \div (14 {x}^{3} ) = \frac{7 {x}^{4} }{14 {x}^{3} } = \frac{1}{2} {x}^{4 - 3} = \frac{1}{2} x = \frac{x}{2}$