Question

necesito ayuda para este despeje​

Answer 1

Respuesta:

Explicación paso a paso:

$\frac{x^{2/3}y+5}{-x^{2/3}y^{2} +5y-2} =2\\\\x^{2/3}y+5 = 2(-x^{2/3}y^{2} +5y-2)\\x^{2/3}y+5 = -2x^{2/3}y^{2} +10y-4\\x^{2/3}y + 2x^{2/3}y^{2} = 10y-4-5\\x^{2/3}( y + 2y^{2}) = 10y - 9\\\\x^{2/3} = \frac{10y - 9}{ y + 2y^{2}} \\\\\sqrt[3]{x^{2} } = \frac{10y - 9}{ y + 2y^{2}}\\\\x^{2} = ( \frac{10y - 9}{ y + 2y^{2}})^{3} \\\\|x| = \sqrt{( \frac{10y - 9}{ y + 2y^{2}})^{3}} \\\\x_{1} = \sqrt{( \frac{10y - 9}{ y + 2y^{2}})^{3}}\\\\x_{2} = -\sqrt{( \frac{10y - 9}{ y + 2y^{2}})^{3}}$