Question

necesito ayuda amigos doy 50 puntos

Answer 1

Respuesta:

Ej62= 8/27 cm^3

Ej63=5,29cm

Ej64= 0,287cm

Ej65=18cm^2

Explicación:

*Ej 62

$v = l ^{3} \\ v = (\frac{2}{3} cm)^{3} \\ v = \frac{8}{27} cm ^{3}$

*Ej 63

${c}^{2} = {a}^{2} + {b}^{2} \\ {a}^{2} = c ^{2} - {b}^{2} \\ a = \sqrt{ {c}^{2} - {b}^{2} } \\ a = \sqrt{ {8}^{2} - {6}^{2} } \\ a = \sqrt{64 - 36} \\ a = \sqrt{28} \\ a = 5.29cm$

*Ej 64

similar al anterior

$c = \sqrt{ {a}^{2} + {b}^{2} } \\ c = \sqrt{0.25 ^{2} + ( \frac{9}{64} )^{2} } \\ c = 0.287m$

*Ej 65

$area = \frac{(base \: mayor + base \: menor) \times altura}{2} \\ a = \frac{(4 + 5) \times 4}{2} \\ a = \frac{9 \times 4}{2} \\ a = \frac{36}{2} \\ a = 18cm^2$