Question

n(3n+1)=2 resolver en ecuaciones de segundo grado
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Answer 1

Respuesta:

Explicación paso a paso:

n(3n+1) = 2

3n^2 + n - 2 = 0

a = 3; b = 1; c = - 2

∆ = b^2 - 4ac

∆ = (1)^2 - 4(3)(-2)

∆ = 1 + 24

∆ = 25

√∆ = √25 = 5

x = - (b)± √∆/2(a)

x = - (1)±5/2(3)

x = - 1±5/6

x1 = - 1+5/6

x1 = 4/6 = 2/3

x2 = - 1 - 5/6

x2= - 6/6 = - 1

CS = {- 1, 2/3}