Question

Multiplicar

m^4+m^2n^2+n^4 por m^2-n^2

Answer 1

Respuesta:

El producto es: $m^{6}-n^{6}$

Explicación paso a paso:

$(m^{4}+m^{2}n^{2}+n^{4})(m^{2}-n^{2} )$

$(m^{4})(m^{2})-(m^{4})(n^{2})+(m^{2}n^{2})(m^{2})-(m^{2}n^{2})(n^{2})+(n^{4})(m^{2})-(n^{4})(n^{2})$

$m^{6}-m^{4}n^{2}+m^{4}n^{2}-m^{2}n^{4}+m^{2}n^{4}-n^{6}$   (simplificamos)

$m^{6}-n^{6}$