Question

Molaridad de 58 gr de AL (OH)3 en .078 L​

Answer 1

Mm Al (OH)3 = 78 g/mol

1. calcular moles

n = masa/Mm

n = 58 g / 78 g/mol

n = 0.744 mol

2. calcular molaridad

M = n (moles) / V(L) solc.

M = 0.744 mols / 0.78 L

M = 0.95 molar