Question

Me puedo ayudar plis, es para mañana por favor ayuda ​

Answer 1

Respuesta:

Explicación paso a paso:

(x + 5)(x - 5) = 11

x² - 5² = 11

x² = 11+25

x² = 36

x = ±$\sqrt{36}$

$x_{1}$ = 6

$x_{2}$ = - 6

(n - 6 )(n - 2) = -9n + 32

n² - 8n + 12 +9n - 32 = 0

n² + n - 20 = 0

(n - 4)(n + 5) = 0

n - 4 = 0   ∧   n + 5 = 0

  $n_{1}$ = 4    ∧    $n_{2}$ = - 5

(x - 2)(x + 3) = x + 19

x² + x - 6 - x - 19 = 0

x² - 25 = 0

x² - 5² = 0

(x + 5)(x - 5) = 0

x + 5 = 0   ∧   x - 5 = 0

  $x_{1}$ = - 5    ∧    $x_{2}$ = 5

$x+4 =\frac{2(x-8)}{x-4}$

(x + 4)(x - 4) = 2(x - 8)

x² - 4² = 2x - 16

x² - 2x = 0

x(x  - 2) = 0

$x_{1}$ = 0    ∧    $x_{2}$ = 2

(x - 7)² + (x + 1)² =7(x - 1)²+43

x² - 14x + 49 + x² + 2x + 1 = 7(x² - 2x - 1) + 43

0 = 5x² - 2x - 14

a = 5  ;  b= -2   ;  c= -14      $x = \frac{-b \±\sqrt{b^{2} -4ac} }{2a}$

$x = \frac{-(-2) \± \sqrt{2^{2} -4.5(-14)} }{2*5}$

$x = \frac{2 \± \sqrt{4 +280} }{10} = \frac{2 \± \sqrt{284} }{10} = \frac{2 \± 2\sqrt{71} }{10}$

$x = \frac{2 \± 2\sqrt{71} }{10}= \frac{1 \± \sqrt{71} }{5}$

$x_{1}$ = $\frac{1 + \sqrt{71} }{5}$    ∧    $x_{2}$ = $\frac{1 - \sqrt{71} }{5}$

$\frac{a-3}{2a-3} =\frac{a-1}{a-2}$

(a - 3)(a - 2) = (2a - 3)(a - 1)

a² - 5a + 6 = 2a² - 2a - 3a + 3

0 = a² - 3

3 = a²

$a_{1}$ = $-\sqrt{3}$    ∧    $a_{2}$ = $\sqrt{3}$

2y(y  - 5) + y(y + 2) = 35

2y² - 10y + y² + 2y - 35 = 0

3y² - 8y - 35 = 0

3y            +7  método del aspa

 y            - 5

(3y + 7)(y - 5) = 0

3y + 7 = 0  ∧  y - 5 = 0

$y_{1}$ = -7/3    ∧    $y_{2}$ = 5