Question

Me pueden explicar cómo resolver esto por favor?

\frac{3a-1}{5} + \frac{2a-7}{5} - \frac{2}{5} [/tex]

Answer 1

Resolvemos.

$\dfrac{3a-1}{5}+ \dfrac{2a-7}{5} = \dfrac{2}{5} \\ \\ \dfrac{3a+2a-1-7}{5} = \dfrac{2}{5} \\ \\ \dfrac{5a-8}{\not{5}} = \dfrac{2}{\not{5}} \\ \\ 5a - 8 = 2 \\ \\ 5a = 10 \\ \\ a = \dfrac{10}{5} \\ \\ \boxed{\boxed{a=2}}$