Question

Me pueden ayudar por favor no le entiendo doy corona Monomios y Polinomios
a) (-x-y)²=

b) (-2m+4n)²=

c) (-10b-8c)²=

d) (-5p+6q)²=

e) (-1/7p+1/5q)²=​

Answer 1

$25p^{2}+60pq+36q^{2}$Respuesta:

Explicación paso a paso:

En todos los ejercicios se aplica la formula del binomio cuadrado

Recuerde:

$(a-b)^{2} = (a)^{2}-2ab+(b) ^{2} \\(a+b)^{2} = (a)^{2}+2ab+(b) ^{2}$

$(-x-y)^{2}$

$(-x)^{2}-2(-x)(y)+(y) ^{2}$

$x^{2}+2xy+y^{2}$

$(-2m+4n)^{2}$

$(-2m)^{2}+2(-2m)(4n)+(4n) ^{2}$

$4m^{2}-16mn+16n^{2}$

$(-10b-8c)^{2}$

$(-10b)^{2}-2(-10b)(8c)+(8c) ^{2}$

$100b^{2}+160bc+64c^{2}$

$(-5p+6q)^{2}$

$(-5p)^{2}+2(-5p)(6q)+(6q) ^{2}$

$25p^{2}-60pq+36q^{2}$

$(-\frac{1}{7}p+\frac{1}{5} q)^{2}$

$(-\frac{1}{7}p)^{2} +2(-\frac{1}{7}p)(\frac{1}{5}q)+(\frac{1}{5} q)^{2}$

$\frac{1}{49}p^{2} -\frac{2}{35}pq+\frac{1}{25} q^{2}$