Question

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Answer 1

Respuesta:

1. M = 0,5 kg

H = 1,6 m

G = 9,8 m/s2

Ep =?

. Calculamos la energia potencial

2.Vox=60cos60=30  

Voy=60sen60=51.96  

x=Voxt=30t  

y=Voyt-4.9t^2=51.96t - 4.9t^2  

como t = T + 0.5  

x=30 ( T + 0.5 ) = 30T + 15  

y=51.96(T+0.5) - 4.9 (T+0.5)^2 =- 4.9T^2 + 47.06T + 24.755  

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proyectil 2  

x= 60cos@ T  

y=60sen@ T - 4.9 T^2  

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igualando x  

30T + 15 = 60 cos @ T  

cos@ = (30 T + 15 ) / (60 T)  

igualando y  

-4.9T^2 + 47.06T + 24.755 = 60sen@ T - 4.9 T^2  

sen @ = (47.06 T + 24.755 )/ (60 T )  

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como (sen@)^2 + (cos @)^2 = 1 se sustituye  

[(47.06 T + 24.755 )/ (60 T )]^2 + [ (30 T + 15 ) / (60 T)]^2 = 1  

(2214.64 T^2 + 2329.94 T + 612.81)/ 3600T^2 + (900T^2 + 900T + 225)/3600T^2 = 1  

(2214.64 T^2 + 2329.94 T + 612.81 + 900T^2 + 900T + 225 ) = 3600T^2  

- 485 T^2 + 3229.94 T + 837.81 = 0  

por formula general se obtiene que  

T=6.9047 segundos.  

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sustituyendo en  

cos@ = (30 T + 15 ) / (60 T)  

cos@ = 0.5362  

@=57.57°  

x= 60cos@ T = (60 cos 57.57 )( 6.9047)=222.25 mts  

y=60sen@ T - 4.9 T^2 = ( 60 sen57.57 )( 6.9074) - 4.9 (6.9074)^2 = 116.021 mts .

3. 10 x 1 sobre 100 = 0.1

2000(0.1)al cuadrado ÷ 2 = 10J

4. la cuatro no se :[