Question

Me pueden ayudar con este ejercicio

Answer 1

Area Trapecio Isoceles = h*[(a+b)/2]

Donde
a = 10 cm
b = 4 cm

h = ?

Area = 28 cm²

28 cm² = h*[(a+b)/2]

28 cm² = h*[(10 + 4)/2]

28 = h*[(14/2)]

28 = 7h

h = 28/7

h = 4

Area Triangulo [BxH]/2

Donde Base = (10 - 4)/2 = 6/2 = 3 cm²

Area Triangulo = [3 x 4]/2 = [12 cm²]/2 = 6cm²

Area sombreada = 6 cm²

Rta: D 6 cm²