Question

Me pueden ayudar a resolver toda esta hoja por favoy no le entiendo ​

Answer 1

Respuesta:

Explicación paso a paso:

$a) \ 25x^2=100\\ x^2=\frac{100}{25}\\ x^2=4\\ x_1=2\ ;x_2=-2\\\\ b)\ x^2-54=-5x^2\\ x^2+5x^2-54=0\\ 6x^2=54\\ x^2=\frac{54}{6}\\ x^2=9\\ x_1=3\ ;x_2=-3\\\\ c)\ 2x^2-32=0\\ x^2=\frac{32}{2}\\ x^2=16\\ x_1=4\ ;x_2=-4\\\\ d)\ 4x^2=0\\ x^2=0\\ x=0\\\\ e)\ 3x^2-24=-9x^2\\ 3x^2+9x^2-24=0\\ 12x^2=24\\ x^2= \frac{24}{12}\\ x^2=2\\ x_1=\sqrt{2}\ ;x_2=-\sqrt{2}$

$a)\ 6x^2-36=0\\ 6x^2=36\\ x^2=\frac{36}{6}\\ x^2=6\\ x_1=\sqrt{6}\ :x_2=-\sqrt{6} \\\\ b)\ 3x^2-4=-x^2\\ 3x^2+x^2-4=0\\ 4x^2=4\\ x^2=\frac{4}{4}\\ x^2=1\\ x_1=1\ ;x_2=-1\\\\ c)\ -15x^2=0\\ x^2=0\\ x=0\\\\ d)\ 10x^2-6x-18=x^2-6x\\ 10x^2-x^2-6x+6x-18=0\\ 9x^2-18=0\\ 9x^2=18\\ x^2\frac{18}{9}\\ x^2=2\\ x_1=\sqrt{2}\ ;x_2=-\sqrt{2}\\\\ e)\ 16x^2+22=0\\ 16x^2=-22\\ x^2=\frac{-22}{16}\\ x_1=\frac{i\sqrt{22} }{4}\ ;x_2=-\frac{i\sqrt{22} }{4}$