Me puedem ayudar porfa y darme el procedimiento completo
le doy gracias y coronas
1/4×[1/7-(-5/4)]=
(2/3-1/4)
_______=
5mas1/2)
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son suma y resta de fracciones simples y reglas de signos:
1/4×[1/7-(-5/4)]
= (1/4)(1/7 + 5/4)
= (1/4)(4/28 + 35/28)
= (1/4)(39/28)
= 39/(4*28)
= 39/112
(2/3-1/4)
_______=
5mas1/2)
(2/3-1/4)/(5 + 1/2)
= (8/12 - 3/12)/(10/2 + 1/2)
= (5/12)/(11/2)
= (5/12)/(2/11)
= (5*2)/(12*11)
= 10/132
1/4×[1/7-(-5/4)]
= (1/4)(1/7 + 5/4)
= (1/4)(4/28 + 35/28)
= (1/4)(39/28)
= 39/(4*28)
= 39/112
(2/3-1/4)
_______=
5mas1/2)
(2/3-1/4)/(5 + 1/2)
= (8/12 - 3/12)/(10/2 + 1/2)
= (5/12)/(11/2)
= (5/12)/(2/11)
= (5*2)/(12*11)
= 10/132
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