Me podrían ayudar por favor
Respuestas a la pregunta
Respuesta:
ECUACIONES CON NÚMERO COMPLEJOS
a) Z + 2i = 2 Z -7
b) 3 Z + 2i = 2 Z – 5
c) 7i + Zi = 2 Z – 11
d) Zi + 9i = -15 + 2 Z
a) Z + 2i = 2 Z -7
Z – 2z = -7 – 2i
-z = (-7-2i):2
-z = -7/2 – i
Z = 7/2 + i
b) 3 Z + 2i = 2 Z – 5
3z – 2z = -5 – 2i
Z = -5 – 2i
c) 7i + Zi = 2 Z – 11
Zi – 2z = -11 – 7i
z.(i-2) = -11 – 7i
Z= -1-7i × -2-i_ =
-2+i -2-i
Z= 22+11i+14i+7i² =
(-2)²-(i)²
Z= 22+11i+14i+7i . (-1) =
4-i²
Z= 22+25i-7 =
4-(-1)
Z= 15+25i =
4-1
Z= 15+25i =
5
Z= 3+5i
d) Zi + 9i = -15 + 2 Z
Zi – 2z = -15-9i
z.(i -2) = -15-9i
Z= -15-9i × -2-i =
-2+i -2-i
Z= 30+15i+18i+9i =
(-2)²-i²
Z= 30+33i-9 =
4+1
Z= 30+33i-9 =
5
Z= 21 + 33 i
5 5
Z1 ÷ Z2 = (3 + 2i) (2 + 5i) / (2 - 5i) (2 + 5i)
= [3(2 + 5i) + 2i (2 + 5i)] / (4 - 25i²), como i² = -1, entonces:
=[6 + 15i + 4i + 10i²] / [4 - 25(-1)]
=[6 + 19i + 10(-1)] / [4 + 25]
=[6 + 19i - 10] / 29
=[-4 + 19i] / 29
= (-4 / 29) + (19 / 29)i
Z2 ÷ Z3 = (2 – 5i) / (7 + 4i) = [(2 - 5i)(7 - 4i)] / [(7 - 4i)(7 + 4i)]
= [2(7 - 4i) - 5i(7 - 4i)] / [(7 - 4i)(7 + 4i)]
= [14 - 8i - 35i + 20i²] / [7² - 16i²]
= [14 - 43i + 20(-1)] / [49 + 16]
= [14 - 20 - 43i] / 65
= [-6 - 43i] / 65
= (-6/65) - (43/65)i
Z1 ÷ Z3 = (3 + 2i) / (7 + 4i) = [(3+2i)(7-4i)] / [(7 + 4i)(7 - 4i)]
=[3(7 - 4i) + 2i (7 - 4i)] / [7² - 16i²]
=[21 - 12i + 14i - 8i²] / [49 + 16]
=[21 + 8 + 2i] / 65
=[29 + 2i] / 65
= (29/65) + (2/65)i
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espero haberte ayudado