Question

me podrían ayudar con esto porfa​

Answer 1

Respuesta:

Explicación paso a paso:

1.

Tg5xCtg(x+12) = 1

Tg5x = 1/Ctg(x+12)

Tg5x = Tg(x+12)

5x = x +12

4x = 12

x = 3

2.

Sen20 = cosa , tg40 = ctgb

20 + a = 90

a = 70

40 + b = 90

b = 50

a + b = 120°

3.

(Sen17Csc17 + tg27ctg27)/cos54sec54

(1 + 1)/1 = 2

4.

a + b = 90

Tga = ctgb

(Tg²b + ctg²a)/tgbctga

(Ctg²a+Ctg²a)/(Ctga)(Ctga)

2Ctg²a/Ctg²a

2