Question

Me lo resuelven porfa,doy corona

Answer 1

Respuesta:

$1) {3}^{2} \times 2 - \sqrt[3]{216} \div ( {2}^{5} \div 16 + {1}^{5} ) + \sqrt{81} = {3}^{2} \times 2 - 6 \div ( 32 \div 16 + 1 ) + 9 = 9 \times 2 - 6 \div (2 + 1) + 9 = 9 \times 2 - 6 \div 3 + 9 = 18 - 2 + 9 = 16 + 9 = 25$

$2) \sqrt{196} + ( {4}^{3} - 6 \times 8 ) \div \sqrt[3]{64} \times {2}^{3} = 14 + (64 - 48) \div 4 + 8 = 14 + 16 \div 4 + 8 = 14 + 4 + 8 = 18 + 8 = 26$