Matemáticas, pregunta formulada por jjjelian, hace 9 meses

me explican

a.x-(3-x)=7-(x+2)

b.1-6×=4×-(3-2×)

c.5x-5 (2×+1)=-3 (4×+5)

d.×-(1-3×)=8×-1​

Respuestas a la pregunta

Contestado por Nubesitaqwq
0

Respuesta:

a. x = \frac{8}{3}

b. x = - \frac{1}{3}

c. x = - \frac{5}{19}

d.  x = -10

Explicación paso a paso:

a. x-(3-x)=7-(x+2)

2x -3 + 3 = - x + 5

2x - 3 + 3 = - x + 5 + 3

2x = - x + 8

2x + x = -x + 8 + x

3x = 8

\frac{3x}{3} = \frac{8}{3}

x = \frac{8}{3}

b. .1-6×=4×-(3-2×)

1 - 6 = 4x - (3 - 2x)

4x  - (3 - 2x) = 1 - 6

4x - (3 - 2x) = -5

6x - 3 = -5

6x - 3 + 3 = -5 + 3

6x = -2

\frac{6x}{6} = \frac{-2}{6}

x = - \frac{1}{3}

c. 5x-5 (2×+1)=-3 (4×+5)

5 (-5) (2x + 1) = -3 (4 x + 5)

-50x - 25 = -12x - 15

-50x - 25 + 25 = -12x - 15 + 25

-50x = -12x + 10

-50x + 12 = -12x  + 10 + 12x

-38x = 10

\frac{-38x}{-38} = \frac{10}{-38}

x = - \frac{5}{19}

d. x-(1-3)=8×-1

x - (1 - 3) = 8 (-1)

x + 2 = 8 (-1)

x + 2 = -8 x 1

x + 2 - 2 = -8 - 2

x = -10

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