Question

me conformo con que me hagan dos ejercicios y les doy los puntos

Answer 1

Resolver.
6 - [ √49 - ( 3+ 5)] - 2(5 - 7) =
6 - [ 7 - ( 8)] - 2( - 2) =
6 - [ 7 - 8] + 4 =
6 - [ - 1] + 4
6 + 1 + 4 =
11

4 + 12 : [ 6 - 3( 4 - 8: 2 + 3)] =
4 + 12 : [ 6 - 3( 4 - 4 + 3)] =
4  +12 : [ 6 - 3( 3)] =
4 + 12 : [ 6 - 9] =
4 + 12 : [ -3 ] =
4 - 4 =
0
 

( - 1)⁴  - ( - 2)³ + 18 : ( - 9) - ( - 4 + √4) =
1 - ( - 8) - 2 - ( - 4 + 2) =
1 + 8 - 2 - ( - 2) =
1 + 8 - 2  + 2 =
1 + 8
9


2x - 3 = 5x + 8
- 3 - 8 = 5x - 2x
- 11 = 3x
-11/3 = x


(x + 3)(x - 3) = 3 ( x - 3)      Simplificamos (x - 3)
x + 3 = 3
x = 3 - 3
x = 0


3/5 + 5/4(1/3 + 1/2) =
3/5 + 5/4(2/6 - 3/6) =
3/5 + 5/4( - 1/6) =
3/5 - 5/24 =
72/120 - 25/120 =
(72 - 25) /120 =
47/120


3: 7/5 + 3/10 . 2/3    En la multiplicacion simplificas el 3
3 . 5/7 + 2/10          2/10 = 1/5 (simplificas)
15/7 + 1/5 =
(15 * 7)/35 + 7/35 =
75/35 + 7/35 =
(75 + 7)/35=
82/35


3/5 . 4/6 - 2/7 : 3/7
(3 . 4)/(5 . 6) - 2/7 . 7/3
12/30 - (2 * 7)/( 3. 7) =      Simplificamos el 7  y  12/30 = 2/5
2/5 - 2/3 =
6/15 - 10/5 =
(6 - 10)/15 =
- 4/15

El ejercicio 5 y 6 no salieron completos.