Question

Me ayudarian a resolver?
A) (4/5-1/2)²×25/3+√1×7/16
B) (5/3+8/9:4/3)-25/21×(1/3)²

Answer 1

- Tarea:

Resolver los cálculos combinados.

- Solución:

° Primer cálculo:

$(\frac{4}{5} - \frac{1}{2})^{2} . \frac{25}{3} + \sqrt{1} . \frac{7}{16} =\\ \\ (\frac{10:5.4-10:2.1}{10})^{2} . \frac{25}{3} + \sqrt{1} . \frac{7}{16} =\\ \\ (\frac{8-5}{10})^{2} . \frac{25}{3} + \sqrt{1} . \frac{7}{16} =\\ \\ ( \frac{3}{10})^{2} . \frac{25}{3} + \sqrt{1} . \frac{7}{16} = \\ \\ \frac{9}{100} . \frac{25}{3} + 1 . \frac{7}{16} = \\ \\ \frac{9.25}{100.3} + \frac{1.7}{1.16} = \\ \\ \frac{225}{300} + \frac{7}{16} = \\ \\ \frac{1200:300.225+1200:16.7}{1200} =$

$\frac{900+525}{1200} = \\ \\ \frac{1425}{1200} = \frac{285}{240} = \frac{57}{48} = \frac{19}{16}$

° Segundo cálculo:

$(\frac{5}{3} + \frac{8}{9} : \frac{4}{3}) - \frac{25}{21} . ( \frac{1}{3})^{2} = \\ \\ (\frac{5}{3} + \frac{8.3}{9.4}) -\frac{25}{21} . (\frac{1}{3})^{2} = \\ \\ (\frac{5}{3} + \frac{24}{36}) - \frac{25}{21} . ( \frac{1}{3})^{2} = \\\ \\ \frac{36:3.5+36:36.24}{36} - \frac{25}{21} . (\frac{1}{3})^{2} =\\ \\ \frac{60+24}{36} -\frac{25}{21} . (\frac{1}{3} )^{2} = \\ \\ \frac{84}{36} -\frac{25}{21} . (\frac{1}{3})^{2} = \\ \\ \frac{84}{36} - \frac{25}{21} .\frac{1}{9} =$

$\frac{84}{36} - \frac{25.1}{21.9} = \\ \\ \frac{83}{36} - \frac{25}{189} = \\ \\ \frac{756:36.83-756:189.25}{756} = \\ \\ \frac{1743-100}{756} = \\ \\ \frac{1643}{756}$