Question

me ayudan resolviendo porfa?

Answer 1

Respuesta:

me ayudan resolviendo porfa?

Explicación paso a paso:

$\frac{8b^{2}+14ab+12a^{2} }{4a+6} \\\\=\frac{2\left(4b^2+7ba+6a^2\right)}{4a+6}\\\\=\frac{2\left(4b^2+7ba+6a^2\right)}{2\left(2a+3\right)}\\=\frac{4b^2+7ba+6a^2}{2a+3}$

$(\frac{1}{3}a+\frac{1}{2}b )^{3} \\=\left(\frac{2a+3b}{6}\right)^3\\=\frac{\left(2a+3b\right)^3}{6^3}\\=\frac{\left(2a+3b\right)^3}{216}$

$(3x^{3} +x^{2} +x+\frac{1}{2} )+(-x+9)\\\\=3x^3+x^2+x+\frac{1}{2}-x+9\\\\=3x^3+x^2+\frac{1}{2}+9\\\\=3x^3+x^2+\frac{19}{2}$

$(a^{4}+11a^{2} -12a-5a^{3})*(-3a+3+a^{2} )\\\\=a^6-8a^5+29a^4-60a^3+69a^2-36a$