Question

Me Ayudan PorFavor :(​

Answer 1

$a) \frac{5x + 4y}{6} + \frac{3x - y}{2} = \\ 6( \frac{5x + 4y}{6} + \frac{3x - y}{2} ) = \\ 5x + 4y + 3(3x - y ) = \\ 5x + 4y + 9x - 3y = \\ (5x + 9x) + (4y - 3y) = \\ 14x + y$

$b) \frac{2a - 3b}{8} - \frac{3a - b}{4} = \\ 8( \frac{2a - 3b}{8} - \frac{3a - b}{4} ) = \\ 2a - 3b - 2 \times (3a - b) = \\ 2a - 3b - 6a + 2b = \\ (2a - 6a) + ( - 3b + 2b) = \\ - 4a + ( - b) = \\ - 4a - b$

$c) \frac{6x - 10y}{2} + \frac{x + 6y}{5} = \\ 10( \frac{6x - 10y}{2} + \frac{x + 6y}{5} ) = \\ 5(6x - 10y) + 2(x + 6y) = \\ 30x - 50y + 2x + 12y = \\ (30x + 2x) + ( - 50y + 12y) = \\ 32x + ( - 38y) = \\ 32x - 38y = \\ 2(16x - 19y)$

$d) \frac{5a - 6b}{2} - \frac{2a + 4b}{3} = \\ 6( \frac{5a - 6b}{2} - \frac{2a + 4b}{3} ) = \\ 3(5a - 6b) - 2(2a + 4b) = \\ 15a - 18b - 4a - 8b = \\ (15a - 4a) + ( - 18b - 8b) = \\ 11a + ( - 26b) = \\ 11a - 26b$

$e) \frac{a + 2b}{4} + \frac{b - 2a}{3} = \\ 12( \frac{a + 2b}{4} + \frac{b - 2a}{3} ) = \\ 3(a + 2b) + 4(b - 2a) = \\ 3a + 6b + 4b - 8a = \\ (3a - 8a) + (6b + 4b) = \\ - 5a + 10b \\ 5( - a + 2b)$

$f) \frac{4x + 5y}{3} - \frac{5x - 6y}{4} = \\ 12( \frac{4x + 5y}{3} - \frac{5x - 6y}{4} ) = \\ 4(4x + 5y) - 3(5x - 6y) = \\ 16x + 20y - 15x + 18y = \\ (16x - 15x) + (20y + 18y) = \\ x + 38y$