Question

me ayudan porfavor .​

Answer 1

Respuesta:

Cateto adyacente = 9

A)

Por pitagoras.

h² = (7)² + (9)²

h² = 49 + 81

h² = 130

h = √130

Sen x = C.O/h

Sen x = 7/11,4

Cosx = CA/h

Cosx = 9/√130

Cosx = 9/11,4

Cot = Ca/CO

Cot = 9/7

Secx = n/CA

secx = 11,4/9

Csc x = h/Co

Cscx = 11,4/7

B)

Hallamos cateto opuesto por Pitagoras.

(13)² = 5² + CO²

169 = 25 + CO²

169 - 25 = CO²

144 = CO²

√144 = CO

12 = CO

Senx = CO/h

Senx = 12/13

Cosx = CA/h

Cosx =  5/13

Tanx = Co/CA

Tanx = 12/5

Ctgx = CA/CO

Cotx = 5/12

Cosc = h/CO

Coscx = 13/12