Question

me ayudan porfa doy coronita​

Answer 1

$k = \frac{ {2}^{x}. {2}^{4} + {2}^{x}. {2}^{3} + {2}^{x} . {2}^{1} }{ {2}^{x} .{2}^{3} + {2}^{x}. {2}^{1} } \\ k = \frac{ {2}^{x}.16 + {2}^{x}.8 + {2}^{x} .2 }{ {2}^{x}.8 + {2}^{x} .2} \\ k = \frac{ {2}^{x}.2(8 + 4 + 1) }{ {2}^{x} .2(4 + 1)} \\ k = \frac{8 + 4 + 1}{4 + 1} \\ k = \frac{13}{5}$

Respuesta: A) 13/5